tag:blogger.com,1999:blog-9170261917486213112.post499847644469228254..comments2024-01-22T09:45:29.790+01:00Comments on Racing Rules of Sailing - Look to Windward: Scoring the MatchesJoshttp://www.blogger.com/profile/10346870418220762709noreply@blogger.comBlogger15125tag:blogger.com,1999:blog-9170261917486213112.post-49020084115355370862010-04-13T21:49:36.210+02:002010-04-13T21:49:36.210+02:00This has been interesting and I almost had the sam...This has been interesting and I almost had the same results as you came up with.<br /><br />I scored the 5 tied boats, but I did not eliminate the races that they sailed against the other boats they were not tied with when figuring out which was their first, second, third race under rule C11.2a. The rule says to break the tie by eliminating the first (then second, then third, etc.)race of the tied boats, but it does not say "between" the tied boats.<br /><br />I don't read the rule to say that you should not score those races, but you deleted the races they sailed with 7 & 8 because everyone beat them. However, you did not eliminate the races they sailed against Monnin, who beat everyone. Anyone who sailed early against Monnin thus has an advantage under this tie-breaking scenario.<br /><br />Don D.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-9170261917486213112.post-7057243959209874692010-04-13T16:49:09.098+02:002010-04-13T16:49:09.098+02:00@Yoram
Gurgel has indeed 4 points if you count all...@Yoram<br />Gurgel has indeed 4 points if you count all. But all the tied competitors have 2 point from races against nrs 7&8, so I'm leaving those out for everybody.Joshttps://www.blogger.com/profile/10346870418220762709noreply@blogger.comtag:blogger.com,1999:blog-9170261917486213112.post-19097989603493262022010-04-13T14:56:26.583+02:002010-04-13T14:56:26.583+02:00I previously posted as Anonymous (#11). my mistake...I previously posted as Anonymous (#11). my mistake was eliminating the 1st match between the TIED competitors and not REGARDLESS, as Jos pointed out.<br />But that means eliminating, for Gurgel, the match with Meyer (1-0), leaving Gurgel with 4 pts, not 2? any comments?yoramnoreply@blogger.comtag:blogger.com,1999:blog-9170261917486213112.post-57019769146825723652010-04-13T12:55:49.468+02:002010-04-13T12:55:49.468+02:00@All
This has been an interesting post - in so far...@All<br />This has been an interesting post - in so far that it shows that the rulebook is not easy in calculating the correct scores.<br /><br />Besides meticulously following the rules in C11 you also need to make sure you double check your arithmetic.<br /><br />Because none of the rules in C11.1 work between these five - and a sail-off was not possible - you need to go to rule C11.3<br />Eliminating the the score for the first match of each tied competitor (regardless against whom they sailed) and then look at the points again.<br /><br />This results in Gurgel as the only one with two points; He's the second one to go through to the final stages. And leaves four. Again we look at these four without the others.<br /><br />By having two points, Kemmling and Walser go through and because Walser won his match against Kemmling he goes through as 3rd. <br />Kemmling is the last who enters the final stages as 4th<br /><br />Den Boer beat Meyer; he becomes fifth, Meyer sixth. Finally of course Sehested and Nyberg.<br /><br />The one advice I can give:<br />Please make sure you have at least two people independently checking this. It is very easy to make a mistake.Joshttps://www.blogger.com/profile/10346870418220762709noreply@blogger.comtag:blogger.com,1999:blog-9170261917486213112.post-43630514670217984032010-04-12T06:43:00.609+02:002010-04-12T06:43:00.609+02:00First tie-breaker, according to C11.3(a), eliminat...First tie-breaker, according to C11.3(a), eliminating score for each 1st race for each tied competitor, results in Meyer being 2nd (after Monnin) and Gurgel 3rd.<br />now to break the tie between the last three: applying C11.1(a), Walser will be 4th, Kemmling 5th, and den Boer 6th.<br />OK, Jos?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-9170261917486213112.post-438914953247116762010-04-11T22:30:09.496+02:002010-04-11T22:30:09.496+02:00Jos,
I've got a question about "eliminati...Jos,<br />I've got a question about "eliminating the score for the first race for each tied competitor" (C 11.3 (a)).<br />Does this refer to the first race of a competitor in that stage, regardless whether this race was against someone he is currently tied with?<br /><br />Thanks a lot<br /><br />MartinMartinhttp://www.heizkoerper-sailingteam.de/noreply@blogger.comtag:blogger.com,1999:blog-9170261917486213112.post-3241490566712123612010-04-11T19:56:58.583+02:002010-04-11T19:56:58.583+02:00OoooPPPSS .. i just sow now the pairing list...
Le...OoooPPPSS .. i just sow now the pairing list...<br />Let me check if the result stands....mamadehttps://www.blogger.com/profile/06606442102533763244noreply@blogger.comtag:blogger.com,1999:blog-9170261917486213112.post-57065727657150567172010-04-11T19:56:58.584+02:002010-04-11T19:56:58.584+02:001° Monin
2° Gurgel
3° Kemmling
4° Walser
5° Den B...1° Monin<br />2° Gurgel<br />3° Kemmling<br />4° Walser<br />5° Den Boer<br />6° Meyer<br />7° Sehested<br />8° Nybergmamadehttps://www.blogger.com/profile/06606442102533763244noreply@blogger.comtag:blogger.com,1999:blog-9170261917486213112.post-66537072361176529232010-04-09T19:46:34.723+02:002010-04-09T19:46:34.723+02:00First Gurgel(C11.3(a)) because he was the only loo...First Gurgel(C11.3(a)) because he was the only looser in his first match.<br />Walser and Kemmling are the next, with Walser winning against Kemmling. (C11.1(a) and C11.1(b))<br />Then Den Boer and Meyer, with Den Boer winning against Meyer (C11.1(a) and C11.1(b))<br />UliAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-9170261917486213112.post-70081105260150836212010-04-09T12:39:08.533+02:002010-04-09T12:39:08.533+02:00Dear Sirs,
In my opinion ranking will be this ...Dear Sirs,<br /><br /> <br /><br />In my opinion ranking will be this way;<br /><br /> <br /><br />1- Monin<br /><br />2- Meyer<br /><br />3- Gurgel<br /><br />4- Walser<br /><br />5- Kemmling<br /><br />6- Den Boer<br /><br />7- Sehested<br /><br />8- Nyberg<br /><br /> <br /><br />Thanks and best regards,<br /><br /> <br /><br />Burak<br /><br /> <br /><br />Tur-NUAnonymoushttps://www.blogger.com/profile/03674361825268149808noreply@blogger.comtag:blogger.com,1999:blog-9170261917486213112.post-34457588540157521342010-04-09T02:30:46.026+02:002010-04-09T02:30:46.026+02:00First apply rule C11.1(a), calculate the scores am...First apply rule C11.1(a), calculate the scores among the five tied boats, excluding scores of those boats against boats not in the tie, thus:<br /><br />Gurgel, 1, 0, 0, 1, total 2<br />Kemling, 0, 1, 1, 0, total 2<br />den Boer, 1, 0, 1, 0, total 2<br />Meyer, 1, 0, 0, 1, total 2<br />Walser, 0, 1, 1, 0, total 2<br /><br />All five boats remain tied.<br /><br />Skip rule C11.1(b) because the tie is between more than two boats.<br /><br />Apply rule C11.1(c)<br /><br />All boats have 0 points against first boat Monnin.<br /><br />All boats are tied for second place.<br /><br />Shested is the next boat behind the tied boats, calculate points against Shested, thus<br /><br />Gurgel, 1, <br />Kemling, 1,<br />den Boer, 1,<br />Meyer, 1,<br />Walser, 1,<br /><br />All five boats remain tied.<br /><br />Skip rule C11.1(d) boats did not sail in different groups.<br /><br />Skip rule C11.1(e) there are no scores in a previous recent stage of the event.<br /><br />Apply rule C11.3, Assuming that a sail-off is not possible: Eliminate the score for the first race for each tied competitor<br /><br />Gurgel, 1st race F1M1 v Meyer, score 0,<br />Kemling, 1st race F3M2 v Meyer, score 1<br />den Boer, 1st race F2M1 v Gurgel, score 1<br />Meyer, 1st race F1M1 v Gurgel, score 1<br />Walser, 1st race F3M1 v den Boer, score 1<br /><br />Applying these adjustments to the boats rr score:<br /><br />Gurgel 4-0=4<br />Kemling 4-1=3<br />den Boer 4-1=3<br />Meyer 4-1=3 <br />Walser 4-1=3<br /><br />Decides Gurgel in 2nd Place.<br /><br />Now start again at rule C11.1(a)<br /><br />Kemling, 1,1,0, total 2<br />den Boer, 0,1,0, total 1<br />Meyer, 0,0,1, total 1<br />Walser, 1,1,0, total 2<br /><br />Now Apply rule 11.1(a) again between Kemling and Walser,<br /><br />Kemling, 0<br />Walser, 1,<br /><br />Decides Walser in 3rd place, and Kemling in 4th place.<br /><br />Apply rule C11.1(a) beteen den Boer and Meyer,<br /><br />den Boer, 1<br />Meyer, 0<br /><br />Decides den Boer in 5th place and Meyer in 6th place.<br /><br />Hope I got the principles and the arithmetic right.Brassnoreply@blogger.comtag:blogger.com,1999:blog-9170261917486213112.post-45383365805996398642010-04-09T00:51:35.396+02:002010-04-09T00:51:35.396+02:001 - Monnin
2 - Gurgel
3 - Kemmling
4 - Meyer
-----...1 - Monnin<br />2 - Gurgel<br />3 - Kemmling<br />4 - Meyer<br />----------------<br />5 - Walser<br />6 - den Boer<br />7 - Sehested<br />8 - Nyberg<br /><br />Don D.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-9170261917486213112.post-41458521677754040742010-04-08T01:23:25.938+02:002010-04-08T01:23:25.938+02:00My order
Monin 1, Gurgel 2, Walser 3, Kemmling 4, ...My order<br />Monin 1, Gurgel 2, Walser 3, Kemmling 4, den Boer 5, Meyer 6, Sehested 7, Nyberg 8.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-9170261917486213112.post-36492483338317498342010-04-08T01:16:21.792+02:002010-04-08T01:16:21.792+02:00Sorry Ignore my previous. I have just read all the...Sorry Ignore my previous. I have just read all the words!! and found the pairing list.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-9170261917486213112.post-80786739424910995642010-04-08T01:14:50.088+02:002010-04-08T01:14:50.088+02:00I believe further information is needed to resolve...I believe further information is needed to resolve this.<br />I would like to know the order of races so I can apply C11.3.Anonymousnoreply@blogger.com